Manuals/calci/SLOG - Revision history

Devika: /* Related Videos */

2019-01-31T20:39:03Z

2019-01-31T20:37:49Z

Examples

2017-05-09T20:16:01Z

Description

2017-05-09T20:10:29Z

2017-05-09T19:59:39Z

Created page with "SLOG"

New page

SLOG

@@ Line 21: / Line 21: @@
 ==Related Videos==
-{{#ev:youtube|v=Z5myJ8dg_Rm|280|center|Log}}
+{{#ev:youtube|v=Z5myJ8dg_rM&t=9s|280|center|Log}}
 ==See Also==

@@ Line 18: / Line 18: @@
 #SLOG(187,3) = 2.3195001328620837
 #SLOG(-342,4) = -2
 ==See Also==

@@ Line 11: / Line 11: @@
 *The two exponentiation function powers and exponentials have two inverse functions roots and logarithms,the two tetration functions tetra powers and tetra exponentials have two inverse functions tetra roots and tetra logarithms also called super roots and super logarithms.
 *The super-logarithm, written <math>slog_{b}{z}</math> is defined implicitly by
-<math>slog_{b}(b^{z}) = slog_{b}{z}+1 </math> and
+ <math>slog_{b}(b^{z}) = slog_{b}{z}+1 </math> and
-<math> slog_{b}(1) = 0</math>
+ <math> slog_{b}(1) = 0</math>

← Older revision		Revision as of 20:10, 9 May 2017
Line 1:		Line 1:
−	SLOG	+	<div style="font-size:30px">'''SLOG (Number,Base)'''</div><br/>
		+	*<math> Number</math> is any real number.
		+	*<math>Base</math> is any positive real number.
		+
		+	==Description==
		+	*This function shows the super logarithm of the given number.
		+	*In <math>SLOG(Number,Base)</math>,<math>Number</math> is the value to find log value.
		+	*<math>Base</math> is the base value of the Log.
		+	*SLOG is the super-logarithm which is one of the two inverse functions of tetration.
		+	*This is also called Tetra logarithm.
		+	*The two exponentiation function powers and exponentials have two inverse functions roots and logarithms,the two tetration functions tetra powers and tetra exponentials have two inverse functions tetra roots and tetra logarithms also called super roots and super logarithms.
		+	*The super-logarithm, written <math>slog_{b}{z}</math> is defined implicitly by
		+	<math>slog_{b}(b^{z}) = slog_{b}{z}+1 </math> and
		+	<math> slog_{b}(1) = 0</math>