Difference between revisions of "RvsZ3"
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===Vectors and assignment=== | ===Vectors and assignment=== | ||
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− | Z3 operates on named data structures. The simplest such structure is the numeric vector,which is a single entity consisting of an ordered collection of numbers. | + | Z3 operates on named data structures. The simplest such structure is the numeric vector, which is a single entity consisting of an ordered collection of numbers. |
</pre> | </pre> | ||
Revision as of 00:50, 7 July 2021
Comparison of R vs Z3
Simple manipulations; numbers and vectors
Vectors and assignment
Z3 operates on named data structures. The simplest such structure is the numeric vector, which is a single entity consisting of an ordered collection of numbers.
To set up a vector named x, say, consisting of five numbers, namely 10.4, 5.6, 3.1, 6.4 and 21.7, use the R command
> x <- c(10.4, 5.6, 3.1, 6.4, 21.7)
Z3 command to set up a vector is:
x<==[10.4, 5.6, 3.1, 6.4, 21.7];
Alternatively we can use the simple "=" also.
x=[10.4, 5.6, 3.1, 6.4, 21.7]
Assignment can also be made using the function ASSIGN(). An equivalent way of making the same assignment as above is with: In R,
> assign("x", c(10.4, 5.6, 3.1, 6.4, 21.7))
In Z3, use the "ASSIGN" function as:
ASSIGN("x", [10.4, 5.6, 3.1, 6.4, 21.7])
Assignments can also be made in the other direction, using the obvious change in the assignment operator. So the same assignment could be made using
[10.4, 5.6, 3.1, 6.4, 21.7]==>x
The reciprocals of the above five values for x in R,
> 1/x
In Z3, We can use the function called Reciprocal,
RECIPROCAL(x) (the value of x is [10.4, 5.6, 3.1, 6.4, 21.7]
Also we can use directly,
([10.4,5.6,3.1,6.4,21.7]<>d40)@(x=>1/x)
The further assignment
> y <- c(x, 0, x)
would create a vector y with 11 entries consisting of two copies of x with a zero in the middle place.
Vector arithmetic
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