Leetcode Solutions and Render3D/RENDER examples.


LEETCODE 1109: bookings = [[1,2,10],[2,3,20],[2,5,25]], n = 5; ro={}; f=(x,y)=>ro[x]=(ro[x]||0) + y; f#; bookings.map(r=>f((r[0])..(r[1]),r[2])); ro KEYTAGS(ro).map(r=>[r[0],SUM(r[1])]) PRINT(ro)

LEETCODE 2491: skill = [3,4]; p = skill.⋰.⁜(2); arr = p[0].mergerows(p[1].reverse()); tar = ∑(arr[0]);

if(arr.filter(r => ≠(∑(r), tar)).length > 0) {

   result = "Not compatible(-1)";

} else{

   result = ∑(arr.$$(✖))

}

PRINT(result);