Changes

68 bytes removed ,  05:31, 18 December 2013
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#=IMLOG10("3i") = 0.477121254719662+0.682188176920921i
 
#=IMLOG10("3i") = 0.477121254719662+0.682188176920921i
 
#=IMLOG10("0") = NULL
 
#=IMLOG10("0") = NULL
*Imln("8") for that it should consider the imaginary value is zero.
      
==See Also==
 
==See Also==
writer
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