Manuals/calci/FRIEDMANTEST

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FRIEDMAN(Array,SignificanceLevel,logicalValue)


  • is the array of values to find the test statistic.
  • is the value between 0 and 1.
  • is either TRUE or FALSE.

Description

  • This function gives the Test statistic summary of FriedMan Test.
  • Friedman's test is a nonparametric test that compares three or more paired groups.
  • It is the alternative to ANOVA with repeated measures.
  • It is used to test for differences between groups when the dependent variable being measured is ordinal.
  • It can also be used for continuous data that has violated the assumptions necessary to run the one-way ANOVA with repeated measures.
  • This test is simelar to the Kruskal Wallis test.
  • The data of the Fried Man test having the following assumptions:
  • 1. One group that is measured on three or more different occasions.
  • 2.Group is a random sample from the population.
  • 3.The dependent variable should be measured at the ordinal or continuous level.
  • 4.Samples do not need to be normally distributed.
  • Steps for Fried man Test:
  • 1.Define Null and Alternative Hypotheses:Null Hypotheses:There is no difference between the conditions.Alternative Hypotheses:There is a difference between the conditions.
  • 2.State Alpha:Alpha=0.05.
  • 3.Calculate degrees of freedom:df = k – 1, where k = number of groups.
  • 4.State Decision Rule:From the Chi squared table calculate the critical value.
  • Suppose the chisquared(symbol)is greater than the critical value then reject the null hypothesis
  • 5.Calculate the Test Statistic:
  • k = number of columns (often called “treatments”)
  • n = number of rows (often called “blocks”)
  • Rj = sum of the ranks in column j.
  • If there is no significant difference between the sum of the ranks of each of the columns, then M will be small, but if at least one column shows significant difference then M will be larger.
  • 6.State Results:In this step we have to take a decision of null hypothesis either accept or reject depending on the critical value table.
  • 7.State Conclusion:To be significant, our obtained U has to be equal to or LESS than this

critical value.

Example

White Red Rose
10 7 8
8 5 5
7 8 6
9 6 4
7 5 7
4 7 5
5 9 3
6 6 7
5 4 6
10 6 4
4 7 4
7 3 3
  1. =FRIEDMANTEST(A1:C13,0.05,TRUE)


TEST-STATISTICS RANKS
White Red Rose
3 1 2
3 1.5 1.5
2 3 1
3 2 1
2.5 1 2.5
1 3 2
2 3 1
1.5 1.5 3
2 1 3
3 2 1
1.5 3 1.5
3 1.5 1.5
ANALYSIS
White Red Rose
Sum Of Ranks 27.5 23.5 21
SS 756.25 552.25 441
Qr 1.7916666666666572
df 2
AsymSig 0.4082672341468858

Related Videos

Friedman Test

See Also

References