Manuals/calci/Examples1 - Revision history

Joseph: /* Unit Conversion Examples */

2021-09-22T05:07:10Z

Unit Conversion Examples

Joseph: /* Unit Conversion Examples */

2021-09-22T05:03:20Z

Unit Conversion Examples

Joseph at 17:21, 19 September 2021

2021-09-19T17:21:03Z

Joseph: /* Unit Conversion Examples */

2021-09-19T05:54:31Z

Unit Conversion Examples

Joseph: /* Unit Conversion Examples */

2021-09-19T05:41:29Z

Unit Conversion Examples

Joseph: /* Unit Conversion Examples */

2021-09-19T05:31:06Z

Unit Conversion Examples

Sahiti at 09:23, 28 September 2018

2018-09-28T09:23:00Z

Abin: /* Unit Conversion Examples */

2018-05-16T09:42:26Z

Unit Conversion Examples

Abin: /* Unit Conversion Examples */

2018-05-16T09:41:08Z

Unit Conversion Examples

Abin: /* Examples */

2018-05-16T09:38:39Z

Examples

@@ Line 753: / Line 753: @@
 delx = 0.1(m)
 FouriersLaw(k,a,delt,delx)
-//16.340543097418998BTUIT2 .N-1 .diffK-1 .h-1 .m-1 .K
+//417.0483BTUIT.h-1.ft-1.diffK-1	90cm2	-140K	0.1m	17240.18562992126BTUIT.diffK-1.h-1.K

@@ Line 729: / Line 729: @@
 <source lang="cpp">
 /*solution in S.I units*/
-FouriersLaw:=[k,a,delt,delx,(-1)<*>(k)<*>a<*>delt</>delx];
+FouriersLaw=(k,a,delt,delx)=>[k,a,delt,delx,(-1)<*>(k)<*>a<*>delt</>delx];
 k = 401("W.m-1.diffK-1")         //
 a = 90(cm2)                    // area
@@ Line 745: / Line 745: @@
 /*solution with SI and Imperial units*/
-FouriersLaw:=[k,a,delt,delx,(-1)<*>(k)<*>a<*>delt</>delx];
+FouriersLaw=(k,a,delt,delx)=>[k,a,delt,delx,(-1)<*>(k)<*>a<*>delt</>delx];
 k = 417.0483("BTUIT*h-1*ft-1*diffK-1")
 a = 90(cm2)
@@ Line 760: / Line 760: @@
 /*solution in imperial units*/
-FouriersLaw:=[k,a,delt,delx,(-1)<*>(k)<*>a<*>delt</>delx];
+FouriersLaw=(k,a,delt,delx)=>[k,a,delt,delx,(-1)<*>(k)<*>a<*>delt</>delx];
 k = 417.0483("BTUIT*h-1*ft-1*diffK-1")
 a = 0.096875(ft2)

@@ Line 705: / Line 705: @@
 mu = 0.4(N.s/m2)<>(cP)
 d = 2(cm)
-ReynoldsNumber(v,d,rho,mu)
+rn=ReynoldsNumber(v,d,rho,mu);
 //112.5

@@ Line 645: / Line 645: @@
 <source lang="cpp">
 /*solution with SI units*/
-FrictionFactor:=[dP,L,D,ρ,U,(dP</>((L</>D)<*>(0.5<*>ρ<*>(U<^>2))))][5];
+FrictionFactor=(dP,L,D,ρ,U)=>[dP,L,D,ρ,U,(dP</>((L</>D)<*>(0.5<*>ρ<*>(U<^>2))))][5];
 dP = 1723.68925(Pa)        // pressure drop
 L = 30.48m                 // pipe length
@@ Line 657: / Line 657: @@
 /*solution with SI and Imperial units*/
-FrictionFactor:=[dP,L,D,ρ,U,(dP</>((L</>D)<*>(0.5<*>ρ<*>(U<^>2))))][5];
+FrictionFactor=(dP,L,D,ρ,U)=>[dP,L,D,ρ,U,(dP</>((L</>D)<*>(0.5<*>ρ<*>(U<^>2))))][5];
 dP = 1723.68925(Pa)
 L = 100ft

@@ Line 729: / Line 729: @@
 /*solution in S.I units*/
 FouriersLaw:=[k,a,delt,delx,(-1)<*>(k)<*>a<*>delt</>delx];
-k = 401(W.m-1.diffK-1)         //
+k = 401("W.m-1.diffK-1")         //
 a = 90(cm2)                    // area
 t1 = 10(degC)<>(degK)          // temperature1
@@ Line 745: / Line 745: @@
 /*solution with SI and Imperial units*/
 FouriersLaw:=[k,a,delt,delx,(-1)<*>(k)<*>a<*>delt</>delx];
-k = 417.0483(BTUIT*h-1*ft-1*diffK-1)
+k = 417.0483("BTUIT*h-1*ft-1*diffK-1")
 a = 90(cm2)
 t1 = 10(degC)<>(degK)
@@ Line 760: / Line 760: @@
 /*solution in imperial units*/
 FouriersLaw:=[k,a,delt,delx,(-1)<*>(k)<*>a<*>delt</>delx];
-k = 417.0483(BTUIT*h-1*ft-1*diffK-1)
+k = 417.0483("BTUIT*h-1*ft-1*diffK-1")
 a = 0.096875(ft2)
 t1 = 10(degC)<>(degK)

@@ Line 669: / Line 669: @@
 /*solution with imperial units*/
-FrictionFactor:=[dP,L,D,ρ,U,(dP</>((L</>D)<*>(0.5<*>ρ<*>U^2)))][5]
+FrictionFactor=(dP,L,D,ρ,U)=>[dP,L,D,ρ,U,(dP</>((L</>D)<*>(0.5<*>ρ<*>U^2)))][5];
 dP = 0.25(psi)
 L = 100ft

@@ Line 58: / Line 58: @@
-<div id="z3code1b" style="font-size:16px">'''z3 code: Using Function'''<img src ="	http://images.zcubes.com/iconset/calci/20180516_LengthParallelContraFlow1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
+<div id="z3code1b" style="font-size:16px">'''z3 code: Using Function'''<img src ="http://images.zcubes.com/iconset/calci/20180516_LengthParallelContraFlow1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
 <source lang="cpp">
 function LengthParallelContraFlow(hg,hw,cpg,cpw,mg,mw,tg1,tg2,tw1,D)

@@ Line 642: / Line 642: @@
 An oil with density(ρ) of 999.834907696(kg/m3) flows through a pipe of length(L) 30.48m and diameter(D) 0.1524m with a nominal velocity(U) of 0.94488(m/s). Pressure drop(dP) in the pipe is 1723.68925(Pa). Find the friction coeffecient.
-<div id="z3codep1" style="font-size:16px">'''z3 code:'''<img src ="			http://images.zcubes.com/iconset/calci/20180502_FrictionFactor1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
+<div id="z3codep1" style="font-size:16px">'''z3 code:'''<img src ="			http://images.zcubes.com/iconset/calci/20180516_FrictionFactor1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
 <source lang="cpp">
 /*solution with SI units*/
@@ Line 685: / Line 685: @@
 <div id="z3codep2" style="font-size:16px">'''z3 code:'''
-<div id="z3codep1" style="font-size:16px">'''z3 code:'''<img src ="			http://images.zcubes.com/iconset/calci/20180502_reynoldsnumber1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
+<div id="z3codep1" style="font-size:16px">'''z3 code:'''<img src ="			http://images.zcubes.com/iconset/calci/20180516_reynoldsnumber1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
 <source lang="cpp">
 /*solution in S.I. units*/
@@ Line 724: / Line 724: @@
 A slab that is made from copper has a length of 10 cm and an area that is 90 cm2. The front side is heated to 150 oC and the back to 10 oC. Find the heat flux q and the heat flow rate Q in the slab once steady state is reached. Assume dT/dx is constant.
-<div id="z3codep3" style="font-size:16px">'''z3 code:'''<img src ="			http://images.zcubes.com/iconset/calci/20180502_Fourier's-Law1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
+<div id="z3codep3" style="font-size:16px">'''z3 code:'''<img src ="			http://images.zcubes.com/iconset/calci/20180516_Fourier's-Law1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
 <source lang="cpp">
 /*solution in S.I units*/
@@ Line 774: / Line 774: @@
 A body is projected with a velocity of 20 ms-1 at 50deg to the horizontal. Find Maximum height reached.
-<div id="z3codep4" style="font-size:16px">'''z3 code:'''<img src ="				http://images.zcubes.com/iconset/calci/20180502_MaximumHeight1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
+<div id="z3codep4" style="font-size:16px">'''z3 code:'''<img src ="				http://images.zcubes.com/iconset/calci/20180516_MaximumHeight1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
 <source lang="cpp">
 /*solution in S.I units*/
@@ Line 811: / Line 811: @@
 frequency does the observer hear? The speed of sound is 340m/s.
-<div id="z3codep5" style="font-size:16px">'''z3 code:'''<img src ="				http://images.zcubes.com/iconset/calci/20180502_DopplerEffect1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
+<div id="z3codep5" style="font-size:16px">'''z3 code:'''<img src ="				http://images.zcubes.com/iconset/calci/20180516_DopplerEffect1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
 <source lang="cpp">
 /*solution in S.I units*/
@@ Line 847: / Line 847: @@
 Circular Segment Area
-<div id="z3codep6" style="font-size:16px">'''z3 code:'''<img src ="				http://images.zcubes.com/iconset/calci/20180502_Circular-Segment-Area1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
+<div id="z3codep6" style="font-size:16px">'''z3 code:'''<img src ="				http://images.zcubes.com/iconset/calci/20180516_Circular-Segment-Area1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
 <source lang="cpp">
 CircularSegmentArea:=[r,α,(r^2<*>(RAD(α)<->DSIN(α))</>2)];
@@ Line 880: / Line 880: @@
 Coulombs Law
-<div id="z3codep7" style="font-size:16px">'''z3 code:'''<img src ="					http://images.zcubes.com/iconset/calci/20180502_Coulomb's-Law1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
+<div id="z3codep7" style="font-size:16px">'''z3 code:'''<img src ="					http://images.zcubes.com/iconset/calci/20180516_Coulomb's-Law1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
 <source lang="cpp">
 CoulombsLaw:=[q1,q2,k,r,q1<*>q2<*>k</>r<^>2];

@@ Line 471: / Line 471: @@
 projection of M1 into M2 is restricted to a vertical distance of 2.5 in. (63.5 mm).<br>
-<div id="z3code4a" style="font-size:16px">'''z3 code: Using Function'''<img src ="	http://images.zcubes.com/iconset/calci/20180516_NotchDesign1.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
+<div id="z3code4a" style="font-size:16px">'''z3 code: Using Function'''<img src ="	http://images.zcubes.com/iconset/calci/20180516_NotchDesign2.jpg" style="margin-left:12px; margin-bottom:12px;width:250px;height:250px;"></div>
 <source lang="cpp">
 function NotchDesign(b,φ,P,Q,F,A){