Manuals/calci/IMDIV - Revision history

Devika at 21:34, 19 July 2018

2018-07-19T21:34:31Z

2018-07-16T21:23:39Z

2017-03-13T13:09:01Z

2015-10-12T06:52:26Z

Examples

2015-06-03T17:07:13Z

ZOS Section

2015-05-29T19:06:46Z

2015-03-27T05:21:56Z

Examples

2014-06-25T10:33:02Z

ZOS Section

2014-04-24T10:06:32Z

2013-12-12T04:33:56Z

References

@@ Line 1: / Line 1: @@
 <div style="font-size:30px">'''IMDIV()'''</div><br/>
-*Parameters are in the form of a+bi.
+*Parameters are any complex numbers of the form of a+ib.
 **IMDIV(),returns the quotient of two complex numbers
@@ Line 18: / Line 18: @@
 ==ZOS==
 *The syntax is to calculate the IMDIV in ZOS is <math>IMDIV()</math>.
-**Parameters are in the form of a+bi.
+**Parameters are any complex numbers of the form of a+ib.
 *For e.g.,IMDIV("3+2i","3-2i")

@@ Line 1: / Line 1: @@
-<div style="font-size:30px">'''IMDIV(ComplexNumber1,ComplexNumber2)'''</div><br/>
+<div style="font-size:30px">'''IMDIV()'''</div><br/>
-*<math>ComplexNumber1</math> and <math>ComplexNumber2</math> are in the form of a+bi.
+*Parameters are in the form of a+bi.
 ==Description==
@@ Line 6: / Line 7: @@
 *This function gives the division of two complex numbers.
 *This function used to remove the <math>i</math> (imaginary unit) from the denominator.
-*<math>ComplexNumber1</math> and <math>ComplexNumber2</math> are in the form  of <math>a+ib</math> and <math>c+id</math>, where <math>a,b,c</math> & <math>d</math> are real numbers <math>i</math> is the imaginary unit, <math>i=\sqrt{-1}</math>.
+*The two Parameters are in the form  of <math>a+ib</math> and <math>c+id</math>, where <math>a,b,c</math> & <math>d</math> are real numbers <math>i</math> is the imaginary unit, <math>i=\sqrt{-1}</math>.
 *Let z1 and z2 are the two Complex Numbers.
 *To do the division of complex number we have follow the steps:
@@ Line 16: / Line 17: @@
 ==ZOS==
-*The syntax is to calculate the IMDIV in ZOS is <math>IMDIV(ComplexNumber1,ComplexNumber2)</math>.
+*The syntax is to calculate the IMDIV in ZOS is <math>IMDIV()</math>.
-**<math>ComplexNumber1</math> and <math>ComplexNumber2</math> are in the form of a+bi.
+**Parameters are in the form of a+bi.
 *For e.g.,IMDIV("3+2i","3-2i")

← Older revision		Revision as of 13:09, 13 March 2017
Line 40:		Line 40:
	==References==		==References==
	[http://en.wikipedia.org/wiki/Complex_division Complex Division]		[http://en.wikipedia.org/wiki/Complex_division Complex Division]
		+
		+
		+
		+	*[[Z_API_Functions \| List of Main Z Functions]]
		+
		+	*[[ Z3 \| Z3 home ]]

@@ Line 24: / Line 24: @@
 ==Examples==
 #IMDIV("4+2i","3-i") =<math>\frac{4+2i}{3-i}*\frac{3+i}{3+i}</math> = <math>\frac{12+10i+2i^2}{3^2-i^2} = 10+\frac{10i}{10}</math> (because <math>i^2=-1</math>) = <math> 1+\frac{i}{1} = 1+1i </math>
-#IMDIV("3-5i,2-6i") = 0.9+0.2i
+#IMDIV("3-5i","2-6i") = 0.9+0.2i
 #IMDIV("5","2+3i") = 0.7692307692307693 + -1.1538461538461537i
 #IMDIV("1+i","2") = 0.5+0.5i

@@ Line 15: / Line 15: @@
 *To find the Conjugate of a Complex Number we can use the function [[Manuals/calci/IMCONJUGATE  | IMCONJUGATE]].
-==ZOS Section==
+==ZOS==
 *The syntax is to calculate the IMDIV in ZOS is <math>IMDIV(ComplexNumber1,ComplexNumber2)</math>.
 **<math>ComplexNumber1</math> and <math>ComplexNumber2</math> are in the form of a+bi.

← Older revision		Revision as of 04:33, 12 December 2013
Line 24:		Line 24:

	==References==		==References==
−	[http://en.wikipedia.org/wiki/Complex_division\| Complex Division]	+	[http://en.wikipedia.org/wiki/Complex_division Complex Division]