Manuals/calci/IMSQRT - Revision history

Devika at 21:05, 18 July 2018

2018-07-18T21:05:47Z

2018-07-18T20:55:02Z

2018-03-21T19:11:58Z

Examples

2018-03-21T19:09:19Z

Description

2018-03-21T19:08:30Z

Description

2017-03-13T13:11:47Z

2015-06-03T17:10:23Z

ZOS Section

2015-05-13T15:45:38Z

2015-04-27T01:24:31Z

2014-07-03T06:21:06Z

ZOS Section

@@ Line 1: / Line 1: @@
 <div style="font-size:30px">'''IMSQRT (ComplexNumber)'''</div><br/>
-*<math>ComplexNumber </math> is of the form <math>z=x+iy</math>
+*<math>ComplexNumber </math> is of the form <math>z=x+iy</math>.
 ==Description==

@@ Line 1: / Line 1: @@
-<div style="font-size:30px">'''IMSQRT(Complexnumber)'''</div><br/>
+<div style="font-size:30px">'''IMSQRT (ComplexNumber)'''</div><br/>
-*<math> complex number </math> is of the form <math>z=x+iy</math>
+*<math>ComplexNumber </math> is of the form <math>z=x+iy</math>
 ==Description==
 *This function gives  square root of a complex number.
-*IMSQRT(z), where z  is  the complex number is in the form of "x+iy".
+*IMSQRT(ComplexNumber), where  complex number is in the form of "x+iy".
 *where x&y are the real numbers.<math>i</math> imaginary unit .<math>i=\sqrt{-1}</math>.
 *The square root of a complex number is defined by:
 <math>\sqrt{z}=\sqrt{x+iy}=\sqrt{r.e^{i\theta}}=\sqrt{{r}(cos(\frac{\theta}{2})+isin(\frac{\theta}{2})}</math>
@@ Line 13: / Line 14: @@
 ==ZOS==
-*The syntax is to calculate square root of a complex number in ZOS is <math>IMSQRT(Complexnumber)</math>.
+*The syntax is to calculate square root of a complex number in ZOS is <math>IMSQRT(ComplexNumber)</math>.
-**<math> complex number </math> is of the form <math>z=x+iy</math>
+**<math>ComplexNumber</math> is of the form <math>z=x+iy</math>
 *For e.g.,IMSQRT("9+10i")
 *IMSQRT(IMSUB("9+10i","-2-3i"))

@@ Line 22: / Line 22: @@
 #=IMSQRT("2+3i")=1.67414922803554+0.895977476129838i
 #=IMSQRT("-4-5i")=1.09615788950152-2.2806933416653i
-#=IMSQRT("7")=2.64575131106459
+#=IMSQRT("7")=2.6457513110645907+ⅈ0
 #=IMSQRT("8i")=2+2i

@@ Line 9: / Line 9: @@
 <math>\sqrt{z}=\sqrt{x+iy}=\sqrt{r.e^{i\theta}}=\sqrt{{r}(cos(\frac{\theta}{2})+isin(\frac{\theta}{2})}</math>
 *where <math>r</math> is the modulus of <math>z</math>. <math>r=\sqrt{x^2+y^2}</math>
-*And <math>\theta</math> is the argument of <math>z</math>. <math> θ=tan^{-1}(y/x)</math> also <math>θ∈(-\pi,\pi]</math>.
+*And <math>\theta</math> is the argument of <math>z</math>. <math> \theta=tan^{-1}(y/x)</math> also <math>\theta \isin (-\pi,\pi]</math>.
 *We can use [[Manuals/calci/COMPLEX| COMPLEX]]  function to convert real and imaginary number in to a complex number.

@@ Line 7: / Line 7: @@
 *where x&y are the real numbers.<math>i</math> imaginary unit .<math>i=\sqrt{-1}</math>.
 *The square root of a complex number is defined by:
-<math>\sqrt{z}=\sqrt{x+iy}=\sqrt{r.e^{i\theta}}=\sqrt{{r}(cos(\frac{θ}{2})+isin(\frac{θ}{2})}</math>
+<math>\sqrt{z}=\sqrt{x+iy}=\sqrt{r.e^{i\theta}}=\sqrt{{r}(cos(\frac{\theta}{2})+isin(\frac{\theta}{2})}</math>
 *where <math>r</math> is the modulus of <math>z</math>. <math>r=\sqrt{x^2+y^2}</math>
 *And <math>\theta</math> is the argument of <math>z</math>. <math> θ=tan^{-1}(y/x)</math> also <math>θ∈(-\pi,\pi]</math>.

← Older revision		Revision as of 13:11, 13 March 2017
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	==References==		==References==
	[http://en.wikipedia.org/wiki/Binary_logarithm Binary Logarithm]		[http://en.wikipedia.org/wiki/Binary_logarithm Binary Logarithm]
		+
		+
		+
		+	*[[Z_API_Functions \| List of Main Z Functions]]
		+
		+	*[[ Z3 \| Z3 home ]]