Difference between revisions of "Manuals/calci/IMSQRT"
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<div style="font-size:30px">'''IMSQRT(Complexnumber)'''</div><br/> | <div style="font-size:30px">'''IMSQRT(Complexnumber)'''</div><br/> | ||
*<math> complex number </math> is of the form <math>z=x+iy</math> | *<math> complex number </math> is of the form <math>z=x+iy</math> | ||
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==Description== | ==Description== | ||
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*This function gives square root of a complex number. | *This function gives square root of a complex number. | ||
*IMSQRT(z), where z is the complex number is in the form of "x+iy". | *IMSQRT(z), where z is the complex number is in the form of "x+iy". | ||
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==Examples== | ==Examples== | ||
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#=IMSQRT("2+3i")=1.67414922803554+0.895977476129838i | #=IMSQRT("2+3i")=1.67414922803554+0.895977476129838i | ||
#=IMSQRT("-4-5i")=1.09615788950152-2.2806933416653i | #=IMSQRT("-4-5i")=1.09615788950152-2.2806933416653i |
Revision as of 09:45, 13 May 2015
IMSQRT(Complexnumber)
- is of the form
Description
- This function gives square root of a complex number.
- IMSQRT(z), where z is the complex number is in the form of "x+iy".
- where x&y are the real numbers. imaginary unit ..
- The square root of a complex number is defined by:
Failed to parse (syntax error): {\displaystyle \sqrt{z}=\sqrt{x+iy}=\sqrt{r.e^{i\theta}}=\sqrt{{r}(cos(\frac{θ}{2})+isin(\frac{θ}{2})}}
- where is the modulus of .
- And is the argument of . Failed to parse (syntax error): {\displaystyle θ=tan^{-1}(y/x)} also Failed to parse (syntax error): {\displaystyle θ∈(-\pi,\pi]} .
- We can use COMPLEX function to convert real and imaginary number in to a complex number.
ZOS Section
- The syntax is to calculate square root of a complex number in ZOS is .
- is of the form
- For e.g.,IMSQRT("9+10i")
- IMSQRT(IMSUB("9+10i","-2-3i"))
Examples
- =IMSQRT("2+3i")=1.67414922803554+0.895977476129838i
- =IMSQRT("-4-5i")=1.09615788950152-2.2806933416653i
- =IMSQRT("7")=2.64575131106459
- =IMSQRT("8i")=2+2i
Related Videos
See Also