Difference between revisions of "Manuals/calci/IMSQRT"

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<math>\sqrt{z}=\sqrt{x+iy}=\sqrt{r.e^{i\theta}}=\sqrt{{r}(cos(\frac{\theta}{2})+isin(\frac{\theta}{2})}</math>
 
<math>\sqrt{z}=\sqrt{x+iy}=\sqrt{r.e^{i\theta}}=\sqrt{{r}(cos(\frac{\theta}{2})+isin(\frac{\theta}{2})}</math>
 
*where <math>r</math> is the modulus of <math>z</math>. <math>r=\sqrt{x^2+y^2}</math>  
 
*where <math>r</math> is the modulus of <math>z</math>. <math>r=\sqrt{x^2+y^2}</math>  
*And <math>\theta</math> is the argument of <math>z</math>. <math> θ=tan^{-1}(y/x)</math> also <math>θ∈(-\pi,\pi]</math>.
+
*And <math>\theta</math> is the argument of <math>z</math>. <math> \theta=tan^{-1}(y/x)</math> also <math>\theta \isin (-\pi,\pi]</math>.
 
*We can use [[Manuals/calci/COMPLEX| COMPLEX]]  function to convert real and imaginary number in to a complex number.
 
*We can use [[Manuals/calci/COMPLEX| COMPLEX]]  function to convert real and imaginary number in to a complex number.
  

Revision as of 13:09, 21 March 2018

IMSQRT(Complexnumber)


  • is of the form

Description

  • This function gives square root of a complex number.
  • IMSQRT(z), where z is the complex number is in the form of "x+iy".
  • where x&y are the real numbers. imaginary unit ..
  • The square root of a complex number is defined by:

  • where is the modulus of .
  • And is the argument of . also .
  • We can use COMPLEX function to convert real and imaginary number in to a complex number.

ZOS

  • The syntax is to calculate square root of a complex number in ZOS is .
    • is of the form
  • For e.g.,IMSQRT("9+10i")
  • IMSQRT(IMSUB("9+10i","-2-3i"))
Imaginary Square Root

Examples

  1. =IMSQRT("2+3i")=1.67414922803554+0.895977476129838i
  2. =IMSQRT("-4-5i")=1.09615788950152-2.2806933416653i
  3. =IMSQRT("7")=2.64575131106459
  4. =IMSQRT("8i")=2+2i

Related Videos

IMSQRT

See Also


References

Binary Logarithm