Difference between revisions of "ZCubes/9801 Patterns"
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| + | ==Code-9801 Patterns== | ||
| + | 1/9801 | ||
| + | ops.on; | ||
| + | a=1d1000/9801 | ||
| + | a.toString() | ||
| + | .split("") | ||
| + | .chunks(2) | ||
| + | SQRT(9801) | ||
| − | + | ops.on; | |
| + | a=1d1000/999^2; | ||
| + | a.toString() | ||
| + | .split("") | ||
| + | .slice(2) | ||
| + | .chunks(3) | ||
<br/> | <br/> | ||
| − | © Copyright 1996- | + | *[[Z3 | Z3 home]] |
| + | *[[Z^3 Language Documentation]] | ||
| + | *[[ZCubes_Videos | ZCubes Videos and Tutorials]] | ||
| + | *[[Main_Page | About ZCubes ]] | ||
| + | <br/> | ||
| + | <br/> | ||
| + | © Copyright 1996-2021, ZCubes, Inc. | ||
Latest revision as of 00:07, 11 March 2021
9801 Patterns
This video demonstrates interesting patterns when we compute 1/9801.
In Z we can compute large decimals. This lets us learn patterns that we find difficult to compute using other tools or manual methods.
Video
Code-9801 Patterns
1/9801
ops.on;
a=1d1000/9801
a.toString()
.split("")
.chunks(2)
SQRT(9801)
ops.on;
a=1d1000/999^2;
a.toString()
.split("")
.slice(2)
.chunks(3)
© Copyright 1996-2021, ZCubes, Inc.