Difference between revisions of "Manuals/calci/IMDIV"
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<div style="font-size:30px">'''IMDIV(z1,z2)'''</div><br/> | <div style="font-size:30px">'''IMDIV(z1,z2)'''</div><br/> | ||
− | *<math>z1<math> and <math>z2<math> are complex numbers. | + | *<math>z1</math> and <math>z2</math> are complex numbers. |
==Description== | ==Description== | ||
*This function gives the division of two complex numbers. | *This function gives the division of two complex numbers. | ||
− | *This function used to remove the <math>i<math> (imaginary unit) from the denominator. | + | *This function used to remove the <math>i</math> (imaginary unit) from the denominator. |
− | *<math>z1,z2</math> are the two complex numbers in the form of <math>z1=a+ib</math> and <math>z2=c+id</math>, where <math>a,b,c<math> & <math>d<math> are real numbers <math>i</math> is the imaginary unit, <math>i=\sqrt{-1}<math>. | + | *<math>z1,z2</math> are the two complex numbers in the form of <math>z1=a+ib</math> and <math>z2=c+id</math>, where <math>a,b,c</math> & <math>d</math> are real numbers <math>i</math> is the imaginary unit, <math>i=\sqrt{-1}</math>. |
*To do the division of complex number we have follow the steps: | *To do the division of complex number we have follow the steps: | ||
step 1: We have to write the complex number is in the fraction form. | step 1: We have to write the complex number is in the fraction form. |
Revision as of 05:29, 25 November 2013
IMDIV(z1,z2)
- and are complex numbers.
Description
- This function gives the division of two complex numbers.
- This function used to remove the (imaginary unit) from the denominator.
- are the two complex numbers in the form of and , where & are real numbers is the imaginary unit, .
- To do the division of complex number we have follow the steps:
step 1: We have to write the complex number is in the fraction form. step 2: To find the conjugate of the denominator. step 3: To mutiply the numerator and denominator with conjugate.
i.e.
Examples
- IMDIV("4+2i","3-i")=(4+2i/3-i)*(3+i/3+i)=(12+10i+2i^2)/(3^2-i^2)=10+10i/10 (because i^2=-1)= 1+i/1=1+i
- IMDIV("3-5i,2-6i")=0.9+0.2i
- IMDIV("5","2+3i")=0.769-1.153i
- IMDIV("1+i","2")=0.5+0.5i
See Also