Manuals/calci/HYPGEOMDIST
HYPGEOMDIST(n1,n2,n3,n4)
- is the sample's success.
- is the sample's size.
- is population's success.
- is the population size.
Description
- This function gives the result of Hypergeometric distribution.
- This distribution is a discrete probability distribution which is contrast to the binomial distribution.
- A hypergeometric random variable is the number of successes that result from a hypergeometric experiment.
- The probability distribution of a hypergeometric random variable is called a hypergeometric distribution.
- In HYPGEOMDIST(n1,n2,n3,n4) where n1 is thenumber of items in the Sample that are classified as successes.
- n2 is the total number of items in the sample.
- n3 is thenumber of items in the population that are classified as successes and n4 is the total number of items in the sample.
- The following conditions are applied to the Hypergeometric distribution:
- This distribution is applies to sampling without replacement from a finite population whose elements can be classified into two categories like success or Failure.
- The population or set to be sampled consists of N individuals, objects,or elements
- Each individual can be success (S) or a failure (F),
and there areM successes in the population.
- A sample of n individuals is selected without replacement in such a way that each subset of size n is equally likely to be chosen. The Hyper geometric probability distribution is:
P(X=x)=h(x;n,M,N)=(M (N-M
x) n-x) /(N n) for x is an integer satisfying max(0, n-N+M)<=x<=min(n,M). where x is sample's success.
- n is the sample's size.
- M is population's success and N is the population size.
- Here we can give any positive real numbers.
- Suppose we are assigning any decimals numbers it will change in to Integers.
- This function will give result as error when
- Any one of the argument is nonnumeric.
- n1<0 or n1 is greater than the smaller value of n2 or n3.
- n1 is less than the bigger of 0 or(n2-n4+n3)
- n2<=0 or n2>n4
- n3<=0 or n3>n4 or n4<=0"
Examples
Draw 6 cards from a deck without replacement. What is the probability of getting two hearts? Here M = 13 number of hearts N = 52 total number of cards so N-M= 52-13= 39 and x=2,n=6 so n-x=6-2=4 HYPGEOMDIST(2,6,13,52)=0.315129882 2.42 balls are numbered 1 - 42. You select six numbers between 1 and 42. What is the probability that they contain (i)match 3? (ii) match 4? (i)Here M= 6,N=42,x=3and n=6 HYPGEOMDIST(3,6,6,42)=0.02722185 (ii)Here M= 6,N=42,x=4and n=6 HYPGEOMDIST(4,6,6,42)=0.001801446 3.
See Also