Manuals/calci/IMDIV

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IMDIV(z1,z2)


  • where 'z1' and 'z2' are complex numbers.

Description

  • This function gives the division of two complex numbers.
  • This function used to remove the I (imaginary unit) from the denominator.
  • In IMDIV(z1,z2), where z1,z2 are the two complex numbers is in the form of z1=a+ib andz2=c+id, where a,b,c &d are real numbers i is the imaginary unit, i=sqrt(-1).
  • To do the division of complex number we have follow the steps:step1: we have to write the complex number is in the fraction form.
  • step 2: To find the conjugate of the denominator.
  • step 3:To mutiply the numerator and denominator with conjugate.

i.e. IMDIV(z1,z2)=(a+ib)/(c+id)=((a+ib)/(c+id))*((c-id)/(c-id))

                            =[(ac+bd)/(c^2+d^2)]+[(bc-ad)i/[(c^2+d^2)]

Examples

  1. IMEXP("2+3i")=-7.315110094901102+1.0427436562359i
  2. IMEXP("4-5i")=15.4874305606508+52.355491418482i
  3. IMEXP("6")=403.428793492735
  4. IMEXP("2i")=-0.416146836547142+0.909297426825682i
  5. IMEXP("0")=1 andIMEXP("0i")=1

See Also

References

Exponential function