IMDIV(z1,z2)
- where 'z1' and 'z2' are complex numbers.
Description
- This function gives the division of two complex numbers.
- This function used to remove the I (imaginary unit) from the denominator.
- In IMDIV(z1,z2), where z1,z2 are the two complex numbers is in the form of z1=a+ib andz2=c+id, where a,b,c &d are real numbers i is the imaginary unit, i=sqrt(-1).
- To do the division of complex number we have follow the steps:step1: we have to write the complex number is in the fraction form.
- step 2: To find the conjugate of the denominator.
- step 3:To mutiply the numerator and denominator with conjugate.
i.e. IMDIV(z1,z2)=(a+ib)/(c+id)=((a+ib)/(c+id))*((c-id)/(c-id))=[(ac+bd)/(c^2+d^2)]+[(bc-ad)i/[(c^2+d^2)]
Examples
- IMDIV("4+2i","3-i")=(4+2i/3-i)*(3+i/3+i)=(12+10i+2i^2)/(3^2-i^2)=10+10i/10 (because i^2=-1)= 1+i/1=1+i
- IMDIV("3-5i,2-6i")=0.9+0.2i
- IMDIV("5","2+3i")=0.769-1.153i
- IMDIV("1+i","2")=0.5+0.5i
See Also