Manuals/calci/FRIEDMANTEST

FRIEDMAN(Array,SignificanceLevel,logicalValue)

• $Array$ is the array of values to find the test statistic.
• $SignificanceLevel$ is the value between 0 and 1.
• $Logicalvalue$ is either TRUE or FALSE.

Description

• This function gives the Test statistic summary of FriedMan Test.
• Friedman's test is a nonparametric test that compares three or more paired groups.
• It is the alternative to ANOVA with repeated measures.
• It is used to test for differences between groups when the dependent variable being measured is ordinal.
• It can also be used for continuous data that has violated the assumptions necessary to run the one-way ANOVA with repeated measures.
• This test is simelar to the Kruskal Wallis test.
• The data of the Fried Man test having the following assumptions:
• 1. One group that is measured on three or more different occasions.
• 2.Group is a random sample from the population.
• 3.The dependent variable should be measured at the ordinal or continuous level.
• 4.Samples do NOT need to be normally distributed.
• Steps for Fried man Test:
• 1.Define Null and Alternative Hypotheses:Null Hypotheses:There is no difference between the conditions.Alternative Hypotheses:There is a difference between the conditions.
• 2.State Alpha:Alpha=0.05.
• 3.Calculate degrees of freedom:df = k – 1, where k = number of groups.
• 4.State Decision Rule:From the Chi squared table calculate the critical value.
• Suppose the chisquared(symbol)is greater than the critical value then reject the null hypothesis
• 5.Calculate the Test Statistic:$M={\frac {12}{nk(k+1)}}\sum _{j=1}^{k}{R_{j}}^{2}-3n(k+1)$
• k = number of columns (often called “treatments”)
• n = number of rows (often called “blocks”)
• Rj = sum of the ranks in column j.
• If there is no significant difference between the sum of the ranks of each of the columns, then M will be small, but if at least one column shows significant difference then M will be larger.
• 6.State Results:In this step we have to take a decision of null hypothesis either accept or reject depending on the critical value table.
• 7.State Conclusion:To be significant, our obtained U has to be equal to or LESS than this

critical value.

Example

Spreadsheet

	A	B	C
1	31	37	38
2	25	20	22
3	42	49	45
4	10	15	17
5	54	56	60

• =FRIEDMANTEST(A1:C5,0.05,TRUE)