Difference between revisions of "CodeReportSolutions"
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Result: 3343 343434 343443 | Result: 3343 343434 343443 | ||
− | # splits string using the postfix regexp pattern. ∪ extracts unique from the results | + | # splits string using the postfix regexp pattern. ∪ extracts unique from the results |
− | + | 12 Character z^3 Solution vs. 14 Character APL Solution | |
==Final Value of Variable After Performing Operations== | ==Final Value of Variable After Performing Operations== |
Revision as of 23:12, 30 July 2024
Code Report Solutions
Following are some simple solutions to videos found on YouTube. Idea is to make it easier for comparing and learning z^3 and other beautiful languages.
Number of Different Integers in a String
Video: https://www.youtube.com/watch?v=59vAjBS3yZM [APL Wins (vs C++, Java & Python)]
z^3 Solution
s="ad3343sadfsd343434df343443sff"; (s#/[^\d]+/)∪
Result: 3343 343434 343443
# splits string using the postfix regexp pattern. ∪ extracts unique from the results 12 Character z^3 Solution vs. 14 Character APL Solution
Final Value of Variable After Performing Operations
Video: https://www.youtube.com/watch?v=8Njxgy4itts [4 APL Solutions in 10 Minutes!]
z^3 Solution
m=["--x","x++","x++"].print(); [0]@(m!)
m! makes this to a function which is evaluated using [0]@. 0 forms a single input combinatorial argument. [0..10]@(m!) can be used to loop through a set of initial values
Interesting that this solution has far less characters than APL solution, and can be made even shorter.
Count Negative Numbers in a Sorted Matrix
Video: https://www.youtube.com/watch?v=pDbDtGn1PXk [LeetCode 176 Problem 1 - Count Negative Numbers in a Sorted Matrix]
z^3 Solution
x=[-2,-1,0;-1,1,3;-1,2,4]; (x⍌).findv(NEGATIVE)#
Gives answer 4
⍌ Flatten Array .findv Gives result of function call NEGATIVE # Counts the result Also note simpler z^3 Array Notation used to create the variable x (with , and ;). Usual Javascript array notations also work.
Check if a matrix is an X-Matrix (X like diagonals are filled)
Video: https://www.youtube.com/watch?v=8ynsN4nJxzU [APL vs BQN vs J vs Q vs NumPy vs Julia vs R - A comparison of seven different programming languages across a few different language criteria.]
z^3 Solution
m=[2 0 0 1; 0 3 1 0; 0 5 2 0; 4 0 0 2]; n=(m#)[0]; xm=|n| |+| |n|.reverse(); xm|==|(m.$("x!=0?1:0"!))
Gives answer true
m# gives length of array m. |n| gives n dimensional Identity Matrix, which is added using |+| to the .reverse() of same array. |==| is used to compare this to the m, .$ is used to apply the function "x!=0?1:0"! to every element. "x!=0?1:0"! shows how a function can be created from a string with the ! operator. Also note simpler z^3 Array Notation used to create the variable x (with , (when positive numbers alone are used, the comma is also optional) and ;). Usual Javascript array notations also work.