Manuals/calci/BIN2OCT
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BIN2OCT(number,places)
- Where 'number' is a binary number to be converted and
- 'places' is the number of characters to be used to display the output.
BIN2OCT converts a binary number to its octal equivalent.
Description
BIN2OCT(number,places)
- 'number' must be a binary number. Binary number is represented using digits 1 or 0 only. The number can also be entered in text format (e.g "101").
- The most significant bit represents the 'sign' of the number (0=positive, 1=negative). Negative numbers are represented using 2's complement notation.
- A number preceding with '0' (e.g 01111111111) should be written in text format ("01111111111") to avoid confusion with octal numbers.
- Calci returns an #ERROR message if 'number' contains more than 10 characters (10 bits).
Need to verify the 'limit for no. of input digits' after next release
- If 'number' is negative, Calci ignores the places, if any and displays 10 digit octal output.
- If 'places' is not an integer, it is truncated.
- If 'places' are nonnumeric, Calci returns an #ERROR message.
- If 'places' is negative, Calci ignores the places and displays the octal output.
For Example,
BIN2OCT(1100100) returns 144
BIN2OCT(100100100,4) returns 0444
BIN2OCT("00111",1.3) returns 07
Examples
| Formula | Octal Output |
| BIN2OCT(100) | 4 |
| BIN2OCT(110011,4) | 0063 |
| BIN2OCT(11001100,6) | 000314 |
| BIN2OCT(1111111111) | 7777777777 |