Changes

<div style="font-size:30px">'''IMDIV(z1,z2)'''</div><br/>

<div style="font-size:30px">'''IMDIV(z1,z2)'''</div><br/>

*where 'z1' and 'z2' are complex numbers.

*<math>z1<math> and <math>z2<math> are complex numbers.

==Description==

==Description==

*This function gives the division of two complex numbers.  

*This function gives the division of two complex numbers.  

*This function used to remove the I (imaginary unit) from the denominator.

*This function used to remove the <math>i<math> (imaginary unit) from the denominator.

*In IMDIV(z1,z2), where z1,z2 are the two complex numbers is in the form of z1=a+ib andz2=c+id, where a,b,c &d are real numbers i is the imaginary unit, i=sqrt(-1).

*<math>z1,z2</math> are the two complex numbers in the form of <math>z1=a+ib</math> and <math>z2=c+id</math>, where <math>a,b,c<math> & <math>d<math> are real numbers <math>i</math> is the imaginary unit, <math>i=\sqrt{-1}<math>.

*To do the division of complex number we have follow the steps:step1: we have to write the complex number is in the fraction form.

*To do the division of complex number we have follow the steps:

*step 2: To find the conjugate of the denominator.

step 1: We have to write the complex number is in the fraction form.

*step 3:To mutiply the numerator and denominator with conjugate.

step 2: To find the conjugate of the denominator.

i.e. IMDIV(z1,z2)=(a+ib)/(c+id)=((a+ib)/(c+id))*((c-id)/(c-id))=[(ac+bd)/(c^2+d^2)]+[(bc-ad)i/[(c^2+d^2)]

step 3: To mutiply the numerator and denominator with conjugate.

i.e. <math>IMDIV(z1,z2) = \frac{a+ib}{c+id} = \frac{a+ib}{c+id}*\frac{c-id}{c-id} =\frac{ac+bd}{c^2+d^2}+\frac{(bc-ad)i}{(c^2+d^2)}

==Examples==

==Examples==