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40 bytes added ,  11:37, 25 November 2013
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==Examples==
 
==Examples==
#IMDIV("4+2i","3-i") = (4+2i/3-i)*(3+i/3+i) = (12+10i+2i^2)/(3^2-i^2) = 10+10i/10 (because <math>i^2=-1</math>) =  1+i/1 = 1+i
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#IMDIV("4+2i","3-i") =<math>\frac{4+2i}{3-i}*\frac{3+i}{3+i}</math> = <math>\frac{12+10i+2i^2}{3^2-i^2}<math> = 10+10i/10 (because <math>i^2=-1</math>) =  1+i/1 = 1+i
 
#IMDIV("3-5i,2-6i")=0.9+0.2i
 
#IMDIV("3-5i,2-6i")=0.9+0.2i
 
#IMDIV("5","2+3i")=0.769-1.153i
 
#IMDIV("5","2+3i")=0.769-1.153i
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