Difference between revisions of "Neet Code Problems"

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n⪥n can be written as n.around(n) also.
 
n⪥n can be written as n.around(n) also.
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==Duplicate Integer==
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Video: https://www.youtube.com/watch?v=3OamzN90kPg [Contains Duplicate - Leetcode 217 - Python]
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Problem Description:
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Given an integer array nums, return true if any value appears more than once in the array, otherwise return false.
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Example 1:
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Input: nums = [1, 2, 3, 3]
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Output: true
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Example 2:
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Input: nums = [1, 2, 3, 4]
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Output: false
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===z^3 Solution===
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<pre>
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n=[1,2,3,1];
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(n∪).$(x=>n⒤x)
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</pre>
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Gives answer
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{| style="" id="TABLE2" class="null wikitable" donotcaption="true" |
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|-
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| 0
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| 3
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|-
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| 1
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|-
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| 2
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|}
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Notes:
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n∪ Uniques of n array
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.$ Apply function to each element
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x=>n⒤x Function x, defined as n find indices that contain x
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≡ can be used to loop to check greater than 1 etc
  
 
=Other Interesting Solutions=
 
=Other Interesting Solutions=

Revision as of 23:49, 11 September 2024

Neet Code Solutions

Thinking in z^3

This is a quick introduction to the z^3 language (pronounced as "zcubes language").

ZCubes Language (z^3) is an easy to write, natural to read, omni-functional language.

Learn z^3 Language in detail by clicking this link.

Introduction

Following are z^3 Solutions to YouTube Code Report Channel Videos. To learn how to code in ZCubes language, please visit [https://coding.zcubes.com]. ZCubes Web Platform can be started in Code Mode at [https://code.zcubes.com].

Problems and Solutions

Products of Array Discluding Self

Video: https://www.youtube.com/watch?v=bNvIQI2wAjk [I ❤ APL and Haskell #2 ]

z^3 Solution

a=[-1,-2,-3,4,3,2,1];
∏±a

Gives answer -1

∏ is Product, ± is SIGN function. APL has 3 characters it its solution (selected as the best solution in the video because of its brevity). Interesting that the solution with z^3 has even less characters, just 2.

Powerful Solution to Indexing Problem (1 character in z^3 vs 3 in APL)

Video: https://www.youtube.com/watch?v=ctbGMuakpHk [Product of Array Except Self - Leetcode 238 - Python]

Problem Description:

Given an integer array nums, return an array output where output[i] is the product of all the elements of nums except nums[i].

Each product is guaranteed to fit in a 32-bit integer.

Follow-up: Could you solve it in O ( n ) O(n) time without using the division operation?

Example 1:

Input: nums = [1,2,4,6]

Output: [48,24,12,8] Example 2:

Input: nums = [-1,0,1,2,3]

Output: [0,-6,0,0,0]

z^3 Solution

n=[1,2,4,6];
n⪥n≡∏

Gives answer

24
12
48
24


n=[-1,1,0,-3,3];
n⪥n≡∏

Gives answer:


0
0
0
0
0


Notes: ⪥ is the .around operator on an array, which takes one or more indices from the second argument to give you an array except that index. ≡∏ Product (∏) conducted by row (≡)

n⪥n can be written as n.around(n) also.


Duplicate Integer

Video: https://www.youtube.com/watch?v=3OamzN90kPg [Contains Duplicate - Leetcode 217 - Python]

Problem Description:

Given an integer array nums, return true if any value appears more than once in the array, otherwise return false.

Example 1:

Input: nums = [1, 2, 3, 3]

Output: true Example 2:

Input: nums = [1, 2, 3, 4]

Output: false

z^3 Solution

n=[1,2,3,1];
(n∪).$(x=>n⒤x)

Gives answer

0 3
1
2


Notes: n∪ Uniques of n array .$ Apply function to each element x=>n⒤x Function x, defined as n find indices that contain x ≡ can be used to loop to check greater than 1 etc

Other Interesting Solutions

See Related