Changes

Manuals/calci/IMDIV (view source)

8 bytes added , 11:35, 25 November 2013

Line 12: Line 12:

==Examples==

−

#IMDIV("4+2i","3-i")=(4+2i/3-i)*(3+i/3+i)=(12+10i+2i^2)/(3^2-i^2) = 10+10i/10 (because <math>i^2=-1</math>)= 1+i/1=1+i

+

#IMDIV("4+2i","3-i") = (4+2i/3-i)*(3+i/3+i) = (12+10i+2i^2)/(3^2-i^2) = 10+10i/10 (because <math>i^2=-1</math>) = 1+i/1 = 1+i

#IMDIV("3-5i,2-6i")=0.9+0.2i

#IMDIV("5","2+3i")=0.769-1.153i

writer

5,435

edits