KRUSKALWALLISTEST
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KRUSKALWALLISTEST(SampleDataByGroup,Confidencelevel,Logicalvalue)
- is the set of values to find the test statistic.
- is the value between 0 and 1.
- is either TRUE or FALSE.
Description
- This function gives the test statistic value of the Kruskal Wallis test.
- It is one type of Non parametric test.
- It is a logical extension of the Wilcoxon-Mann-Whitney Test.
- The parametric equivalent of the Kruskal-Wallis test is the one-way analysis of variance (ANOVA).
- This test is used for comparing more than two sample that are independent or not related.
- It is used to test the null hypothesis that all populations have identical distribution functions against the alternative hypothesis that at least two of the samples differ only with respect to Median.
- Kruskal–Wallis is also used when the examined groups are of unequal size.
- When the Kruskal-Wallis test leads to significant results, then at least one of the samples is different from the other samples.
- The test does not identify where the differences occur or how many differences actually occur.
- Since it is a non-parametric method, the Kruskal–Wallis test does not assume a normal distribution of the residuals, unlike the analogous one-way analysis of variance.
- However, the test does assume an identically shaped and scaled distribution for each group, except for any difference in medians.
- The Kruskal Wallis test data are having the following properties:
- 1.The data points must be independent from each other.
- 2.The distributions do not have to be normal and the variances do not have to be equal.
- 3.The data points must be more than five per sample.
- 4.All individuals must be selected at random from the population.
- 5.All individuals must have equal chance of being selected.
- 6.Sample sizes should be as equal as possible but some differences are allowed.
- Steps for Kruskal Wallis Test:
- 1. Define Null and Alternative Hypotheses:
- Null Hypotheses:There is no difference between the conditions.
- Alternative Hypotheses:There is a difference between the conditions.
- 2.State Alpha:Alpha=0.05.
- 3.Calculate degrees of freedom:df = k – 1, where k = number of groups.
- 4.State Decision Rule:From the Chi squared table calculate the critical value.
- Suppose the is greater than the critical value then reject the null hypothesis
- 5.Calculate the Test Statistic:
- 6.State Results:In this step we have to take a decision of null hypothesis either accept or reject depending on the critical value table.
- 7.State Conclusion:To be significant, our obtained H has to be equal to or LESS than this critical value.
Example
| A | B | C | |
|---|---|---|---|
| 1 | 46 | 44 | 26 |
| 2 | 32 | 31 | 49 |
| 3 | 42 | 25 | 33 |
| 4 | 45 | 22 | 19 |
| 5 | 45 | 22 | 19 |
| 6 | 37 | 30 | 31 |
| 7 | 44 | 30 | 38 |
| 8 | 47 | 19 | 50 |
| 9 | 49 | 40 | |
| 10 | 41 |
=KRUSKALWALLISTEST([(A1:A10),(B1:B10),(C1:C10)],0.05,true)
| GROUP-0 | GROUP-1 | GROUP2 |
|---|---|---|
| 46 | 44 | 26 |
| 32 | 31 | 49 |
| 42 | 25 | 33 |
| 45 | 22 | 19 |
| 45 | 22 | 19 |
| 37 | 30 | 31 |
| 44 | 30 | 38 |
| 47 | 19 | 50 |
| 49 | 40 | undefined |
| 41 | undefined | undefined |
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References