Manuals/calci/IMDIVTWO

IMDIVTWO(ComplexNumber1,ComplexNumber2)

• $ComplexNumber1$ and $ComplexNumber2$ are in the form of a+bi.

Description

• This function gives the division of two complex numbers.
• $ComplexNumber1$ and $ComplexNumber2$ are in the form of $a+ib$ and $c+id$, where $a,b,c$ & $d$ are real numbers $i$ is the imaginary unit, $i={\sqrt {-1}}$.
• Let z1 and z2 are the two Complex Numbers.
• To do the division of complex number we have follow three steps:

step 1: Write the complex number in the fraction form.
step 2: Find the conjugate of the denominator.
step 3: Multiply the numerator and denominator with conjugate.

$IMDIVTWO(z1,z2)={\frac {a+ib}{c+id}}={\frac {a+ib}{c+id}}*{\frac {c-id}{c-id}}={\frac {ac+bd}{c^{2}+d^{2}}}+{\frac {(bc-ad)i}{(c^{2}+d^{2})}}$.

• To find the Conjugate of a Complex Number we can use the function IMCONJUGATE.

ZOS

• The syntax to calculate the IMDIVTWO in ZOS is $IMDIVTWO(ComplexNumber1,ComplexNumber2)$.
  • $ComplexNumber1$ and $ComplexNumber2$ are in the form of a+bi.
• For e.g.,IMDIVTWO("3+2i","3-2i")

ImDiv

Examples

1. IMDIVTWO("4+2i","3-i") = 1+i1
2. IMDIVTWO("-3-5i","-6i") = 0.8333333333333334-i0.5
3. IMDIVTWO("5-2i","2+3i","6+2i") = 0.3076923076923077-i1.4615384615384615
4. IMDIVTWO("1+i","-2i") = -0.5+i0.5

Related Videos

Dividing Complex Numbers

See Also

• IMDIV
• IMPRODUCTTWO
• COMPLEX
• IMAGINARY
• IMREAL

References

Complex Division

• List of Main Z Functions

• Z3 home